What is the extreme f(x,y)=x^2-y^2-xy+4x-2y ?

The extreme f(x,y)=x^2-y^2-xy+4x-2y is Saddle(-2,0)

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extreme f(x,y)=x^2-y^2-xy+4x-2y

extreme

Saddle (- 2, 0)

Solution steps

Find the critical points:

(- 2, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 5

Check the sign of at each critical point

Check critical point

(- 2, 0) :

Saddle

Saddle (- 2, 0)

What is the extreme f(x,y)=x^2-y^2-xy+4x-2y ?
The extreme f(x,y)=x^2-y^2-xy+4x-2y is Saddle(-2,0)