What is the extreme f(x)=(x-4)^2+(y-4)^2-4/(sqrt(5)) ?

The extreme f(x)=(x-4)^2+(y-4)^2-4/(sqrt(5)) is Minimum(4,4)

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extreme f(x)=(x-4)^2+(y-4)^2-4/(sqrt(5))

extreme

Minimum (4, 4)

Solution steps

Find the critical points:

(4, 4)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(4, 4) :

Minimum

Minimum (4, 4)

What is the extreme f(x)=(x-4)^2+(y-4)^2-4/(sqrt(5)) ?
The extreme f(x)=(x-4)^2+(y-4)^2-4/(sqrt(5)) is Minimum(4,4)