What is the extreme f(x)=-x^4+4x^2-2 ?

The extreme f(x)=-x^4+4x^2-2 is Maximum(-sqrt(2),2),Minimum(0,-2),Maximum(sqrt(2),2)

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extreme f(x)=-x^4+4x^2-2

extreme

Maximum (- 2, 2), Minimum (0, - 2), Maximum (2, 2)

Solution steps

f^{'} (x) = - 4 x^{3} + 8 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 2

into

- x^{4} + 4 x^{2} - 2 : 2

Maximum (- 2, 2)

Plug

x = 0

into

- x^{4} + 4 x^{2} - 2 : - 2

Minimum (0, - 2)

Plug

x = 2

into

- x^{4} + 4 x^{2} - 2 : 2

Maximum (2, 2)

Maximum (- 2, 2), Minimum (0, - 2), Maximum (2, 2)

What is the extreme f(x)=-x^4+4x^2-2 ?
The extreme f(x)=-x^4+4x^2-2 is Maximum(-sqrt(2),2),Minimum(0,-2),Maximum(sqrt(2),2)