What is the extreme f(x)=(sqrt(5^2-x^2))/x ?

The extreme f(x)=(sqrt(5^2-x^2))/x is Maximum(-5,0),Minimum(5,0)

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extreme f(x)=(sqrt(5^2-x^2))/x

extreme

Maximum (- 5, 0), Minimum (5, 0)

Solution steps

f^{'} (x) = - \frac{25}{x ^{2} 25 - x ^{2}}

Find intervals:

Decreasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5

Plug

x = - 5

into

\frac{5 ^{2} - x ^{2}}{x} : 0

Maximum (- 5, 0)

Plug

x = 5

into

\frac{5 ^{2} - x ^{2}}{x} : 0

Minimum (5, 0)

Maximum (- 5, 0), Minimum (5, 0)

What is the extreme f(x)=(sqrt(5^2-x^2))/x ?
The extreme f(x)=(sqrt(5^2-x^2))/x is Maximum(-5,0),Minimum(5,0)