What is the extreme f(x,y)=-6x^2-3xy-3y^2-69x-9y+7 ?

The extreme f(x,y)=-6x^2-3xy-3y^2-69x-9y+7 is Maximum(-43/7 , 11/7)

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extreme f(x,y)=-6x^2-3xy-3y^2-69x-9y+7

extreme

Maximum (- \frac{43}{7}, \frac{11}{7})

Solution steps

Find the critical points:

(- \frac{43}{7}, \frac{11}{7})

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = 63

Check the sign of at each critical point

Check critical point

(- \frac{43}{7}, \frac{11}{7}) :

Maximum

Maximum (- \frac{43}{7}, \frac{11}{7})

What is the extreme f(x,y)=-6x^2-3xy-3y^2-69x-9y+7 ?
The extreme f(x,y)=-6x^2-3xy-3y^2-69x-9y+7 is Maximum(-43/7 , 11/7)