What is the extreme f(x)=6x+7x^{(6/7)} ?

The extreme f(x)=6x+7x^{(6/7)} is Minimum(-1,1),Maximum(0,0)

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extreme f(x)=6x+7x^{(6/7)}

extreme

Minimum (- 1, 1), Maximum (0, 0)

Solution steps

f^{'} (x) = 6 + \frac{6}{x ^{\frac{1}{7}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

6 x + 7 x^{\frac{6}{7}} : 1

Minimum (- 1, 1)

Plug

x = 0

into

6 x + 7 x^{\frac{6}{7}} : 0

Maximum (0, 0)

Minimum (- 1, 1), Maximum (0, 0)

What is the extreme f(x)=6x+7x^{(6/7)} ?
The extreme f(x)=6x+7x^{(6/7)} is Minimum(-1,1),Maximum(0,0)