What is the extreme f(x)=x^3-9x^2+7 ?

The extreme f(x)=x^3-9x^2+7 is Maximum(0,7),Minimum(6,-101)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^3-9x^2+7

extreme

Maximum (0, 7), Minimum (6, - 101)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{3} - 9 x^{2} + 7 : 7

Maximum (0, 7)

Plug

x = 6

into

x^{3} - 9 x^{2} + 7 : - 101

Minimum (6, - 101)

Maximum (0, 7), Minimum (6, - 101)

What is the extreme f(x)=x^3-9x^2+7 ?
The extreme f(x)=x^3-9x^2+7 is Maximum(0,7),Minimum(6,-101)