What is the extreme f(x)=2x^3-33x^2+180x+6 ?

The extreme f(x)=2x^3-33x^2+180x+6 is Maximum(5,331),Minimum(6,330)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=2x^3-33x^2+180x+6

extreme

Maximum (5, 331), Minimum (6, 330)

Solution steps

f^{'} (x) = 6 x^{2} - 66 x + 180

Find intervals:

Increasing

: - \infty < x < 5,

Decreasing

: 5 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 5

into

2 x^{3} - 33 x^{2} + 180 x + 6 : 331

Maximum (5, 331)

Plug

x = 6

into

2 x^{3} - 33 x^{2} + 180 x + 6 : 330

Minimum (6, 330)

Maximum (5, 331), Minimum (6, 330)

What is the extreme f(x)=2x^3-33x^2+180x+6 ?
The extreme f(x)=2x^3-33x^2+180x+6 is Maximum(5,331),Minimum(6,330)