What is the extreme f(x)=(x+1)^7-7x-3 ?

The extreme f(x)=(x+1)^7-7x-3 is Maximum(-2,10),Minimum(0,-2)

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extreme f(x)=(x+1)^7-7x-3

extreme

Maximum (- 2, 10), Minimum (0, - 2)

Solution steps

Find the critical points:

x = - 2, x = 0

Domain of

(x + 1)^{7} - 7 x - 3 : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug the extreme point

x = - 2

into

(x + 1)^{7} - 7 x - 3 \Rightarrow y = 10

Maximum (- 2, 10)

Plug the extreme point

x = 0

into

(x + 1)^{7} - 7 x - 3 \Rightarrow y = - 2

Minimum (0, - 2)

Maximum (- 2, 10), Minimum (0, - 2)

What is the extreme f(x)=(x+1)^7-7x-3 ?
The extreme f(x)=(x+1)^7-7x-3 is Maximum(-2,10),Minimum(0,-2)