What is the extreme f(x)=4x^4-2(4)^2x^3 ?

The extreme f(x)=4x^4-2(4)^2x^3 is Saddle(0,0),Minimum(6,-1728)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=4x^4-2(4)^2x^3

extreme

Saddle (0, 0), Minimum (6, - 1728)

Solution steps

f^{'} (x) = 16 x^{3} - 96 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

4 x^{4} - 2 4^{2} x^{3} : 0

Saddle (0, 0)

Plug

x = 6

into

4 x^{4} - 2 4^{2} x^{3} : - 1728

Minimum (6, - 1728)

Saddle (0, 0), Minimum (6, - 1728)

What is the extreme f(x)=4x^4-2(4)^2x^3 ?
The extreme f(x)=4x^4-2(4)^2x^3 is Saddle(0,0),Minimum(6,-1728)