What is the extreme f(x,y)=18x^2-3y^2-36x-128y-110 ?

The extreme f(x,y)=18x^2-3y^2-36x-128y-110 is Saddle(1,-64/3)

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extreme f(x,y)=18x^2-3y^2-36x-128y-110

extreme

Saddle (1, - \frac{64}{3})

Solution steps

Find the critical points:

(1, - \frac{64}{3})

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = - 216

Check the sign of at each critical point

Check critical point

(1, - \frac{64}{3}) :

Saddle

Saddle (1, - \frac{64}{3})

What is the extreme f(x,y)=18x^2-3y^2-36x-128y-110 ?
The extreme f(x,y)=18x^2-3y^2-36x-128y-110 is Saddle(1,-64/3)