What is the extreme f(x)=x^2-9,-3<= x<= 4 ?

The extreme f(x)=x^2-9,-3<= x<= 4 is Maximum(-3,0),Minimum(0,-9),Maximum(4,7)

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extreme f(x)=x^2-9,-3<= x<= 4

extreme

Maximum (- 3, 0), Minimum (0, - 9), Maximum (4, 7)

Solution steps

Find the critical points:

x = - 3, x = 0, x = 4

Domain of

x^{2} - 9, - 3 \leq x \leq 4 : - 3 \leq x \leq 4

Find intervals:

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 4

Plug the extreme point

x = - 3

into

x^{2} - 9 \Rightarrow y = 0

Maximum (- 3, 0)

Plug the extreme point

x = 0

into

x^{2} - 9 \Rightarrow y = - 9

Minimum (0, - 9)

Plug the extreme point

x = 4

into

x^{2} - 9 \Rightarrow y = 7

Maximum (4, 7)

Maximum (- 3, 0), Minimum (0, - 9), Maximum (4, 7)

What is the extreme f(x)=x^2-9,-3<= x<= 4 ?
The extreme f(x)=x^2-9,-3<= x<= 4 is Maximum(-3,0),Minimum(0,-9),Maximum(4,7)