What is the extreme f(x)=-x^3+27x-62 ?

The extreme f(x)=-x^3+27x-62 is Minimum(-3,-116),Maximum(3,-8)

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extreme f(x)=-x^3+27x-62

extreme

Minimum (- 3, - 116), Maximum (3, - 8)

Solution steps

f^{'} (x) = - 3 x^{2} + 27

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 3

into

- x^{3} + 27 x - 62 : - 116

Minimum (- 3, - 116)

Plug

x = 3

into

- x^{3} + 27 x - 62 : - 8

Maximum (3, - 8)

Minimum (- 3, - 116), Maximum (3, - 8)

What is the extreme f(x)=-x^3+27x-62 ?
The extreme f(x)=-x^3+27x-62 is Minimum(-3,-116),Maximum(3,-8)