What is the extreme (9x)/(x^2+36) ?

The extreme (9x)/(x^2+36) is Minimum(-6,-3/4),Maximum(6, 3/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme (9x)/(x^2+36)

extreme

Minimum (- 6, - \frac{3}{4}), Maximum (6, \frac{3}{4})

Solution steps

f^{'} (x) = \frac{9 ( - x ^{2} + 36 )}{( x ^{2} + 36 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = - 6

into

\frac{9 x}{x ^{2} + 36} : - \frac{3}{4}

Minimum (- 6, - \frac{3}{4})

Plug

x = 6

into

\frac{9 x}{x ^{2} + 36} : \frac{3}{4}

Maximum (6, \frac{3}{4})

Minimum (- 6, - \frac{3}{4}), Maximum (6, \frac{3}{4})

What is the extreme (9x)/(x^2+36) ?
The extreme (9x)/(x^2+36) is Minimum(-6,-3/4),Maximum(6, 3/4)