What is the extreme f(x)=2x^3-3x^2-36x+54 ?

The extreme f(x)=2x^3-3x^2-36x+54 is Maximum(-2,98),Minimum(3,-27)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=2x^3-3x^2-36x+54

extreme

Maximum (- 2, 98), Minimum (3, - 27)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 2

into

2 x^{3} - 3 x^{2} - 36 x + 54 : 98

Maximum (- 2, 98)

Plug

x = 3

into

2 x^{3} - 3 x^{2} - 36 x + 54 : - 27

Minimum (3, - 27)

Maximum (- 2, 98), Minimum (3, - 27)

What is the extreme f(x)=2x^3-3x^2-36x+54 ?
The extreme f(x)=2x^3-3x^2-36x+54 is Maximum(-2,98),Minimum(3,-27)