What is the extreme f(x)=x^3-3x+11 ?

The extreme f(x)=x^3-3x+11 is Maximum(-1,13),Minimum(1,9)

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extreme f(x)=x^3-3x+11

extreme

Maximum (- 1, 13), Minimum (1, 9)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x + 11 : 13

Maximum (- 1, 13)

Plug

x = 1

into

x^{3} - 3 x + 11 : 9

Minimum (1, 9)

Maximum (- 1, 13), Minimum (1, 9)

What is the extreme f(x)=x^3-3x+11 ?
The extreme f(x)=x^3-3x+11 is Maximum(-1,13),Minimum(1,9)