What is the extreme f(x)=x^2+2y^2+x^2y+11 ?

The extreme f(x)=x^2+2y^2+x^2y+11 is Minimum(0,0),Saddle(2,-1),Saddle(-2,-1)

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extreme f(x)=x^2+2y^2+x^2y+11

extreme

Minimum (0, 0), Saddle (2, - 1), Saddle (- 2, - 1)

Solution steps

Find the critical points:

(0, 0), (2, - 1), (- 2, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 4

D (x, y) = 4 (2 y + 2) - 4 x^{2}

Check the sign of at each critical point

Check critical point

(0, 0) :

Minimum

Check critical point

(2, - 1) :

Saddle

Check critical point

(- 2, - 1) :

Saddle

Minimum (0, 0), Saddle (2, - 1), Saddle (- 2, - 1)

What is the extreme f(x)=x^2+2y^2+x^2y+11 ?
The extreme f(x)=x^2+2y^2+x^2y+11 is Minimum(0,0),Saddle(2,-1),Saddle(-2,-1)