What is the extreme (x^2-1)(x^2-9) ?

The extreme (x^2-1)(x^2-9) is Minimum(-sqrt(5),-16),Maximum(0,9),Minimum(sqrt(5),-16)

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extreme (x^2-1)(x^2-9)

extreme

Minimum (- 5, - 16), Maximum (0, 9), Minimum (5, - 16)

Solution steps

f^{'} (x) = 4 x (x + 5) (x - 5)

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

(x^{2} - 1) (x^{2} - 9) : - 16

Minimum (- 5, - 16)

Plug

x = 0

into

(x^{2} - 1) (x^{2} - 9) : 9

Maximum (0, 9)

Plug

x = 5

into

(x^{2} - 1) (x^{2} - 9) : - 16

Minimum (5, - 16)

Minimum (- 5, - 16), Maximum (0, 9), Minimum (5, - 16)

What is the extreme (x^2-1)(x^2-9) ?
The extreme (x^2-1)(x^2-9) is Minimum(-sqrt(5),-16),Maximum(0,9),Minimum(sqrt(5),-16)