What is the extreme f(x)=-0.4x^2+90x-2000 ?

The extreme f(x)=-0.4x^2+90x-2000 is Maximum(225/2 ,3062.5)

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extreme f(x)=-0.4x^2+90x-2000

extreme

Maximum (\frac{225}{2}, 3062.5)

Solution steps

f^{'} (x) = - 0.8 x + 90

Find intervals:

Increasing

: - \infty < x < \frac{225}{2},

Decreasing

: \frac{225}{2} < x < \infty

Plug

x = \frac{225}{2}

into

- 0.4 x^{2} + 90 x - 2000 : 3062.5

Maximum (\frac{225}{2}, 3062.5)

What is the extreme f(x)=-0.4x^2+90x-2000 ?
The extreme f(x)=-0.4x^2+90x-2000 is Maximum(225/2 ,3062.5)