What is the extreme ((x^2-8))/(x-3) ?

The extreme ((x^2-8))/(x-3) is Maximum(2,4),Minimum(4,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme ((x^2-8))/(x-3)

extreme

Maximum (2, 4), Minimum (4, 8)

Solution steps

f^{'} (x) = \frac{x ^{2} - 6 x + 8}{( x - 3 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 3,

Decreasing

: 3 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 2

into

\frac{x ^{2} - 8}{x - 3} : 4

Maximum (2, 4)

Plug

x = 4

into

\frac{x ^{2} - 8}{x - 3} : 8

Minimum (4, 8)

Maximum (2, 4), Minimum (4, 8)

What is the extreme ((x^2-8))/(x-3) ?
The extreme ((x^2-8))/(x-3) is Maximum(2,4),Minimum(4,8)