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Beliebt Funktionen >

extreme f(x)=x^2+(240)/x

Lösung

extrempunkte

f (x) = x^{2} + \frac{240}{x}

Lösung

Minimum (2315, 12 \cdot 1 5^{\frac{2}{3}})

Schritte zur Lösung

f^{'} (x) = 2 x - \frac{240}{x ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Absteigend

: 0 < x < 2315,

Ansteigend

: 2315 < x < \infty

Stecke

x = 2315

in

x^{2} + \frac{240}{x} : 12 \cdot 1 5^{\frac{2}{3}}

Minimum (2315, 12 \cdot 1 5^{\frac{2}{3}})

Graph

Beliebte Beispiele

extreme f(x)=x+(13)/x

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