What is the extreme f(x,y)=-4x^2-2y^2-8x+12y+5 ?

The extreme f(x,y)=-4x^2-2y^2-8x+12y+5 is Maximum(-1,3)

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extreme f(x,y)=-4x^2-2y^2-8x+12y+5

extreme

Maximum (- 1, 3)

Solution steps

Find the critical points:

(- 1, 3)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = 32

Check the sign of at each critical point

Check critical point

(- 1, 3) :

Maximum

Maximum (- 1, 3)

What is the extreme f(x,y)=-4x^2-2y^2-8x+12y+5 ?
The extreme f(x,y)=-4x^2-2y^2-8x+12y+5 is Maximum(-1,3)