What is the extreme f(x)=3x^4-294x^2+5 ?

The extreme f(x)=3x^4-294x^2+5 is Minimum(-7,-7198),Maximum(0,5),Minimum(7,-7198)

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extreme f(x)=3x^4-294x^2+5

extreme

Minimum (- 7, - 7198), Maximum (0, 5), Minimum (7, - 7198)

Solution steps

f^{'} (x) = 12 x^{3} - 588 x

Find intervals:

Decreasing

: - \infty < x < - 7,

Increasing

: - 7 < x < 0,

Decreasing

: 0 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 7

into

3 x^{4} - 294 x^{2} + 5 : - 7198

Minimum (- 7, - 7198)

Plug

x = 0

into

3 x^{4} - 294 x^{2} + 5 : 5

Maximum (0, 5)

Plug

x = 7

into

3 x^{4} - 294 x^{2} + 5 : - 7198

Minimum (7, - 7198)

Minimum (- 7, - 7198), Maximum (0, 5), Minimum (7, - 7198)

What is the extreme f(x)=3x^4-294x^2+5 ?
The extreme f(x)=3x^4-294x^2+5 is Minimum(-7,-7198),Maximum(0,5),Minimum(7,-7198)