What is the extreme f(x)=(x^2-14x+49)/(x-9) ?

The extreme f(x)=(x^2-14x+49)/(x-9) is Maximum(7,0),Minimum(11,8)

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extreme f(x)=(x^2-14x+49)/(x-9)

extreme

Maximum (7, 0), Minimum (11, 8)

Solution steps

f^{'} (x) = \frac{x ^{2} - 18 x + 77}{( x - 9 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 7,

Decreasing

: 7 < x < 9,

Decreasing

: 9 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = 7

into

\frac{x ^{2} - 14 x + 49}{x - 9} : 0

Maximum (7, 0)

Plug

x = 11

into

\frac{x ^{2} - 14 x + 49}{x - 9} : 8

Minimum (11, 8)

Maximum (7, 0), Minimum (11, 8)

What is the extreme f(x)=(x^2-14x+49)/(x-9) ?
The extreme f(x)=(x^2-14x+49)/(x-9) is Maximum(7,0),Minimum(11,8)