What is the extreme f(x)=x^3-12x^2+80 ?

The extreme f(x)=x^3-12x^2+80 is Maximum(0,80),Minimum(8,-176)

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extreme f(x)=x^3-12x^2+80

extreme

Maximum (0, 80), Minimum (8, - 176)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 8,

Increasing

: 8 < x < \infty

Plug

x = 0

into

x^{3} - 12 x^{2} + 80 : 80

Maximum (0, 80)

Plug

x = 8

into

x^{3} - 12 x^{2} + 80 : - 176

Minimum (8, - 176)

Maximum (0, 80), Minimum (8, - 176)

What is the extreme f(x)=x^3-12x^2+80 ?
The extreme f(x)=x^3-12x^2+80 is Maximum(0,80),Minimum(8,-176)