What is the extreme f(x)= 1/x-(64)/y+xy ?

The extreme f(x)= 1/x-(64)/y+xy is Maximum(-1/4 ,16)

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extreme f(x)= 1/x-(64)/y+xy

extreme

Maximum (- \frac{1}{4}, 16)

Solution steps

Find the critical points:

(- \frac{1}{4}, 16)

\frac{\partial ^{2} f}{\partial x ^{2}} = - \frac{128}{y ^{3}}

D (x, y) = - \frac{256}{x ^{3} y ^{3}} - 1

Check the sign of at each critical point

Check critical point

(- \frac{1}{4}, 16) :

Maximum

Maximum (- \frac{1}{4}, 16)

What is the extreme f(x)= 1/x-(64)/y+xy ?
The extreme f(x)= 1/x-(64)/y+xy is Maximum(-1/4 ,16)