What is the extreme f(x,y)=x^2+y^3-6xy+3x+6y-2 ?

The extreme f(x,y)=x^2+y^3-6xy+3x+6y-2 is Minimum(27/2 ,5),Saddle(3/2 ,1)

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extreme f(x,y)=x^2+y^3-6xy+3x+6y-2

extreme

Minimum (\frac{27}{2}, 5), Saddle (\frac{3}{2}, 1)

Solution steps

Find the critical points:

(\frac{27}{2}, 5), (\frac{3}{2}, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 6 y

D (x, y) = 12 y - 36

Check the sign of at each critical point

Check critical point

(\frac{27}{2}, 5) :

Minimum

Check critical point

(\frac{3}{2}, 1) :

Saddle

Minimum (\frac{27}{2}, 5), Saddle (\frac{3}{2}, 1)

What is the extreme f(x,y)=x^2+y^3-6xy+3x+6y-2 ?
The extreme f(x,y)=x^2+y^3-6xy+3x+6y-2 is Minimum(27/2 ,5),Saddle(3/2 ,1)