What is the extreme y=(-8-8x^2)/(2sqrt(x)(1+x)) ?

The extreme y=(-8-8x^2)/(2sqrt(x)(1+x)) is Maximum(1,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme y=(-8-8x^2)/(2sqrt(x)(1+x))

extreme

Maximum (1, - 4)

Solution steps

f^{'} (x) = - \frac{2 ( x ^{3} + 3 x ^{2} - 3 x - 1 )}{x x ( x + 1 ) ^{2}}

Find intervals:

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

\frac{- 8 - 8 x ^{2}}{2 x ( 1 + x )} : - 4

Maximum (1, - 4)

What is the extreme y=(-8-8x^2)/(2sqrt(x)(1+x)) ?
The extreme y=(-8-8x^2)/(2sqrt(x)(1+x)) is Maximum(1,-4)