What is the extreme f(x)=9x^3-54x^2+81x+13,(-6,2) ?

The extreme f(x)=9x^3-54x^2+81x+13,(-6,2) is Maximum(1,49)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=9x^3-54x^2+81x+13,(-6,2)

extreme

Maximum (1, 49)

Solution steps

Find the critical points:

x = 1

Domain of

9 x^{3} - 54 x^{2} + 81 x + 13, (- 6, 2) : - 6 < x < 2

Find intervals:

Increasing

: - 6 < x < 1,

Decreasing

: 1 < x < 2

Plug the extreme point

x = 1

into

9 x^{3} - 54 x^{2} + 81 x + 13 \Rightarrow y = 49

Maximum (1, 49)

What is the extreme f(x)=9x^3-54x^2+81x+13,(-6,2) ?
The extreme f(x)=9x^3-54x^2+81x+13,(-6,2) is Maximum(1,49)