What is the extreme f(x)=(2e^{3x})/(-3x-1) ?

The extreme f(x)=(2e^{3x})/(-3x-1) is Maximum(0,-2)

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extreme f(x)=(2e^{3x})/(-3x-1)

extreme

Maximum (0, - 2)

Solution steps

f^{'} (x) = - \frac{18 e ^{3 x} x}{( - 3 x - 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Increasing

: - \frac{1}{3} < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{2 e ^{3 x}}{- 3 x - 1} : - 2

Maximum (0, - 2)

What is the extreme f(x)=(2e^{3x})/(-3x-1) ?
The extreme f(x)=(2e^{3x})/(-3x-1) is Maximum(0,-2)