What is the extreme f(x)=1-x^3-3x-2x^2+3x^4 ?

The extreme f(x)=1-x^3-3x-2x^2+3x^4 is Minimum(0.91397…,-2.08268…)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=1-x^3-3x-2x^2+3x^4

extreme

Minimum (0.91397 \dots, - 2.08268 \dots)

Solution steps

Find the critical points:

x \approx 0.91397 \dots

Domain of

1 - x^{3} - 3 x - 2 x^{2} + 3 x^{4} : - \infty < x < \infty

Find intervals:

Decreasing

: - \infty < x < 0.91397 \dots,

Increasing

: 0.91397 \dots < x < \infty

Plug the extreme point

x = 0.91397 \dots

into

1 - x^{3} - 3 x - 2 x^{2} + 3 x^{4} \Rightarrow y = - 2.08268 \dots

Minimum (0.91397 \dots, - 2.08268 \dots)

What is the extreme f(x)=1-x^3-3x-2x^2+3x^4 ?
The extreme f(x)=1-x^3-3x-2x^2+3x^4 is Minimum(0.91397…,-2.08268…)