What is the extreme f(x)=x^3-x^2-x+6 ?

The extreme f(x)=x^3-x^2-x+6 is Maximum(-1/3 , 167/27),Minimum(1,5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^3-x^2-x+6

extreme

Maximum (- \frac{1}{3}, \frac{167}{27}), Minimum (1, 5)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 1

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - x^{2} - x + 6 : \frac{167}{27}

Maximum (- \frac{1}{3}, \frac{167}{27})

Plug

x = 1

into

x^{3} - x^{2} - x + 6 : 5

Minimum (1, 5)

Maximum (- \frac{1}{3}, \frac{167}{27}), Minimum (1, 5)

What is the extreme f(x)=x^3-x^2-x+6 ?
The extreme f(x)=x^3-x^2-x+6 is Maximum(-1/3 , 167/27),Minimum(1,5)