What is the extreme f(x)=x^4-8x^3+6 ?

The extreme f(x)=x^4-8x^3+6 is Saddle(0,6),Minimum(6,-426)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^4-8x^3+6

extreme

Saddle (0, 6), Minimum (6, - 426)

Solution steps

f^{'} (x) = 4 x^{3} - 24 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{4} - 8 x^{3} + 6 : 6

Saddle (0, 6)

Plug

x = 6

into

x^{4} - 8 x^{3} + 6 : - 426

Minimum (6, - 426)

Saddle (0, 6), Minimum (6, - 426)

What is the extreme f(x)=x^4-8x^3+6 ?
The extreme f(x)=x^4-8x^3+6 is Saddle(0,6),Minimum(6,-426)