What is the extreme f(x)=x^3-3x^2-9x+15 ?

The extreme f(x)=x^3-3x^2-9x+15 is Maximum(-1,20),Minimum(3,-12)

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extreme f(x)=x^3-3x^2-9x+15

extreme

Maximum (- 1, 20), Minimum (3, - 12)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 15 : 20

Maximum (- 1, 20)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 15 : - 12

Minimum (3, - 12)

Maximum (- 1, 20), Minimum (3, - 12)

What is the extreme f(x)=x^3-3x^2-9x+15 ?
The extreme f(x)=x^3-3x^2-9x+15 is Maximum(-1,20),Minimum(3,-12)