What is the extreme f(x)=3cos^2(x),0<= x<= pi ?

The extreme f(x)=3cos^2(x),0<= x<= pi is Maximum(0,3),Minimum(pi/2 ,0),Maximum(pi,3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=3cos^2(x),0<= x<= pi

extreme

Maximum (0, 3), Minimum (\frac{π}{2}, 0), Maximum (π, 3)

Solution steps

Find the critical points:

x = 0, x = \frac{π}{2}, x = π

Domain of

3 cos^{2} (x), 0 \leq x \leq π : 0 \leq x \leq π

Find intervals:

Decreasing

: 0 < x < \frac{π}{2},

Increasing

: \frac{π}{2} < x < π

Plug the extreme point

x = 0

into

3 cos^{2} (x) \Rightarrow y = 3

Maximum (0, 3)

Plug the extreme point

x = \frac{π}{2}

into

3 cos^{2} (x) \Rightarrow y = 0

Minimum (\frac{π}{2}, 0)

Plug the extreme point

x = π

into

3 cos^{2} (x) \Rightarrow y = 3

Maximum (π, 3)

Maximum (0, 3), Minimum (\frac{π}{2}, 0), Maximum (π, 3)

What is the extreme f(x)=3cos^2(x),0<= x<= pi ?
The extreme f(x)=3cos^2(x),0<= x<= pi is Maximum(0,3),Minimum(pi/2 ,0),Maximum(pi,3)