What is the extreme f(x,y)=2x^3-y^2-6xy+23 ?

The extreme f(x,y)=2x^3-y^2-6xy+23 is Maximum(-3,9),Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x,y)=2x^3-y^2-6xy+23

extreme

Maximum (- 3, 9), Saddle (0, 0)

Solution steps

Find the critical points:

(- 3, 9), (0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 24 x - 36

Check the sign of at each critical point

Check critical point

(- 3, 9) :

Maximum

Check critical point

(0, 0) :

Saddle

Maximum (- 3, 9), Saddle (0, 0)

What is the extreme f(x,y)=2x^3-y^2-6xy+23 ?
The extreme f(x,y)=2x^3-y^2-6xy+23 is Maximum(-3,9),Saddle(0,0)