What is the extreme f(x)=(x^2-11)/(x-6) ?

The extreme f(x)=(x^2-11)/(x-6) is Maximum(1,2),Minimum(11,22)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=(x^2-11)/(x-6)

extreme

Maximum (1, 2), Minimum (11, 22)

Solution steps

f^{'} (x) = \frac{x ^{2} - 12 x + 11}{( x - 6 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 6,

Decreasing

: 6 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = 1

into

\frac{x ^{2} - 11}{x - 6} : 2

Maximum (1, 2)

Plug

x = 11

into

\frac{x ^{2} - 11}{x - 6} : 22

Minimum (11, 22)

Maximum (1, 2), Minimum (11, 22)

What is the extreme f(x)=(x^2-11)/(x-6) ?
The extreme f(x)=(x^2-11)/(x-6) is Maximum(1,2),Minimum(11,22)