What is the extreme f(x,y)=2x^2+2xy+2y^2-6x ?

The extreme f(x,y)=2x^2+2xy+2y^2-6x is Minimum(2,-1)

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extreme f(x,y)=2x^2+2xy+2y^2-6x

extreme

Minimum (2, - 1)

Solution steps

Find the critical points:

(2, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 4

D (x, y) = 12

Check the sign of at each critical point

Check critical point

(2, - 1) :

Minimum

Minimum (2, - 1)

What is the extreme f(x,y)=2x^2+2xy+2y^2-6x ?
The extreme f(x,y)=2x^2+2xy+2y^2-6x is Minimum(2,-1)