What is the extreme f(x,y)=2y^2+2xy+x^2-16x-20y ?

The extreme f(x,y)=2y^2+2xy+x^2-16x-20y is Minimum(6,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x,y)=2y^2+2xy+x^2-16x-20y

extreme

Minimum (6, 2)

Solution steps

Find the critical points:

(6, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = 4

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(6, 2) :

Minimum

Minimum (6, 2)

What is the extreme f(x,y)=2y^2+2xy+x^2-16x-20y ?
The extreme f(x,y)=2y^2+2xy+x^2-16x-20y is Minimum(6,2)