What is the domain of f(x)=sqrt(2x^2+5x-12) ?

The domain of f(x)=sqrt(2x^2+5x-12) is x = 3/2

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domain of f(x)=sqrt(2x^2+5x-12)

domain

x \leq - 4 or x \geq \frac{3}{2}

Interval Notation

(- \infty, - 4] \cup [\frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq \frac{3}{2}

The function domain

x \leq - 4 or x \geq \frac{3}{2}

What is the domain of f(x)=sqrt(2x^2+5x-12) ?
The domain of f(x)=sqrt(2x^2+5x-12) is x<=-4\lor x>= 3/2