What is the domain of 1/(\frac{5){-8x-10}+2} ?

The domain of 1/(\frac{5){-8x-10}+2} is x -15/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of 1/(\frac{5){-8x-10}+2}

domain

x < - \frac{5}{4} or - \frac{5}{4} < x < - \frac{15}{16} or x > - \frac{15}{16}

Interval Notation

(- \infty, - \frac{5}{4}) \cup (- \frac{5}{4}, - \frac{15}{16}) \cup (- \frac{15}{16}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{15}{16}, x = - \frac{5}{4}

The function domain

x < - \frac{5}{4} or - \frac{5}{4} < x < - \frac{15}{16} or x > - \frac{15}{16}

What is the domain of 1/(\frac{5){-8x-10}+2} ?
The domain of 1/(\frac{5){-8x-10}+2} is x<-5/4 \lor-5/4 <x<-15/16 \lor x>-15/16