What is the domain of f(t)=sqrt(2t^2+5t-3) ?

The domain of f(t)=sqrt(2t^2+5t-3) is t = 1/2

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domain of f(t)=sqrt(2t^2+5t-3)

domain

t \leq - 3 or t \geq \frac{1}{2}

Interval Notation

(- \infty, - 3] \cup [\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

t \leq - 3 or t \geq \frac{1}{2}

The function domain

t \leq - 3 or t \geq \frac{1}{2}

What is the domain of f(t)=sqrt(2t^2+5t-3) ?
The domain of f(t)=sqrt(2t^2+5t-3) is t<=-3\lor t>= 1/2