What is the domain of (x/(x^2+1))/(x/(x^4-1)) ?

The domain of (x/(x^2+1))/(x/(x^4-1)) is x 1

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domain of (x/(x^2+1))/(x/(x^4-1))

domain

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

What is the domain of (x/(x^2+1))/(x/(x^4-1)) ?
The domain of (x/(x^2+1))/(x/(x^4-1)) is x<-1\lor-1<x<0\lor 0<x<1\lor x>1