What is the domain of (ln(x^2))/(x^2-1) ?

The domain of (ln(x^2))/(x^2-1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of (ln(x^2))/(x^2-1)

domain

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < 0 or x > 0

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

What is the domain of (ln(x^2))/(x^2-1) ?
The domain of (ln(x^2))/(x^2-1) is x<-1\lor-1<x<0\lor 0<x<1\lor x>1