What is the domain of f(x)=sqrt((2-x)/(x^2-9)) ?

The domain of f(x)=sqrt((2-x)/(x^2-9)) is x<-3\lor 2<= x<3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=sqrt((2-x)/(x^2-9))

domain

x < - 3 or 2 \leq x < 3

Interval Notation

(- \infty, - 3) \cup [2, 3)

Solution steps

Find non-negative values for radicals:

x < - 3 or 2 \leq x < 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or 2 \leq x < 3

What is the domain of f(x)=sqrt((2-x)/(x^2-9)) ?
The domain of f(x)=sqrt((2-x)/(x^2-9)) is x<-3\lor 2<= x<3