What is the domain of f(x)= 1/((\frac{1){(x-3)})-7} ?

The domain of f(x)= 1/((\frac{1){(x-3)})-7} is x 22/7

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domain of f(x)= 1/((\frac{1){(x-3)})-7}

domain

x < 3 or 3 < x < \frac{22}{7} or x > \frac{22}{7}

Interval Notation

(- \infty, 3) \cup (3, \frac{22}{7}) \cup (\frac{22}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{22}{7}, x = 3

The function domain

x < 3 or 3 < x < \frac{22}{7} or x > \frac{22}{7}

What is the domain of f(x)= 1/((\frac{1){(x-3)})-7} ?
The domain of f(x)= 1/((\frac{1){(x-3)})-7} is x<3\lor 3<x< 22/7 \lor x> 22/7