What is the domain of f(x)=sqrt(3x-12)+6/(x-3) ?

The domain of f(x)=sqrt(3x-12)+6/(x-3) is x>= 4

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domain of f(x)=sqrt(3x-12)+6/(x-3)

domain

f (x) = 3 x - 12 + \frac{6}{x - 3}

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \geq 4

What is the domain of f(x)=sqrt(3x-12)+6/(x-3) ?
The domain of f(x)=sqrt(3x-12)+6/(x-3) is x>= 4