What is the domain of f(x)=sqrt(x^2-9),x>= 3 ?

The domain of f(x)=sqrt(x^2-9),x>= 3 is x>= 3

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domain of f(x)=sqrt(x^2-9),x>= 3

domain

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Set the domain to the given interval

x \geq 3

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

Join real regions with the domain:

(x \leq - 3 or x \geq 3) and x \geq 3

x \geq 3

What is the domain of f(x)=sqrt(x^2-9),x>= 3 ?
The domain of f(x)=sqrt(x^2-9),x>= 3 is x>= 3