What is the domain of f(x)=-1/(2(6+x)^{3/2)} ?

The domain of f(x)=-1/(2(6+x)^{3/2)} is x>-6

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domain of f(x)=-1/(2(6+x)^{3/2)}

domain

x > - 6

Interval Notation

(- 6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = - 6

Combine real regions and undefined points for final function domain

x > - 6

What is the domain of f(x)=-1/(2(6+x)^{3/2)} ?
The domain of f(x)=-1/(2(6+x)^{3/2)} is x>-6