What is the domain of f(x)= 1/(\sqrt[3]{7-2x)} ?

The domain of f(x)= 1/(\sqrt[3]{7-2x)} is x 7/2

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domain of f(x)= 1/(\sqrt[3]{7-2x)}

domain

x < \frac{7}{2} or x > \frac{7}{2}

Interval Notation

(- \infty, \frac{7}{2}) \cup (\frac{7}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{7}{2}

The function domain

x < \frac{7}{2} or x > \frac{7}{2}

What is the domain of f(x)= 1/(\sqrt[3]{7-2x)} ?
The domain of f(x)= 1/(\sqrt[3]{7-2x)} is x< 7/2 \lor x> 7/2